PHP获得跳转的真实地址实例
现在有很多的短网址应用,点击就跳转到缩短之前的网址了,那今天我们就来看一下,PHP如何获取短网址跳转之前的网址,其实也很简单,就是用php的get_headers 函数,取得Response Headers,之后慢慢分析就行了。
给出具体实现方法,代码如下:
<?php $header = get_headers($url, 1); if (strpos($header[0], '301') || strpos($header[0], '302')) { if (is_array($header['Location'])) { return $header['Location'][count($header['Location']) - 1]; } else { return $header['Location']; } } else { return $url; } ?>
实例二,代码如下:
<?php echo get_redirect_url('http://www.phprm.com'); //输出结果为:http://code.google.com/android/ function get_redirect_url($url) { $redirect_url = null; $url_parts = @parse_url($url); if (!$url_parts) return false; if (!isset($url_parts['host'])) return false; //can't process relative URLs if (!isset($url_parts['path'])) $url_parts['path'] = '/'; $sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80) , $errno, $errstr, 30); if (!$sock) return false; $request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?' . $url_parts['query'] : '') . " HTTP/1.1rn"; $request.= 'Host: ' . $url_parts['host'] . "rn"; $request.= "Connection: Closernrn"; fwrite($sock, $request); $response = ''; while (!feof($sock)) $response.= fread($sock, 8192); fclose($sock); if (preg_match('/^Location: (.+?)$/m', $response, $matches)) { if (substr($matches[1], 0, 1) == "/") return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]); else return trim($matches[1]); } else { return false; } }
文章网址:http://www.phprm.com/develop/fs1135.html
随意转载^^但请附上教程地址。