php ajax实现用户登录并且快速实现用户验证,有需要的朋友可参考参考。
核心代码
代码如下 |
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<script type="text/javascript"> $(document).ready(function() { $("#login").click(function() { var action = $("#form1").attr('action'); var form_data = { username: $("#username").val(), password: $("#password").val(), is_ajax: 1 }; $.ajax({ type: "POST", url: action, data: form_data, success: function(response) { if(response == 'success') $("#form1").slideUp('slow', function() { $("#message").html("<p class='success'>登陆成功!</p>"); }); else $("#message").html("<p class='error'>用户名或密码错误.</p>"); } }); return false; }); }); </script> |
index.php源码
代码如下 |
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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>PHP Login with jQuery AJAX</title> <style> body, input { font-family: Georgia, "Times New Roman", Times, serif; } #content { background-color: #eee; width: 300px; margin: 0 auto; border: 1px solid #aaa; -moz-border-radius: 10px; -moz-box-shadow: 0 0 10px #aaa; -webkit-border-radius: 10px; -webkit-box-shadow: 0 0 10px #aaa; padding: 10px; } #form1 label { display: block; font-size: 16px; line-height: 25px; } #form1 input[type=text], #form1 input[type=password] { padding: 2px; font-size: 16px; line-height: 20px; width: 250px; } #form1 input[type=submit] { font-size: 20px; font-weight: bold; padding: 5px; } .success { color: #060; } .error { color: red; } </style> <script type="text/javascript" src="jquery-1.5.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#login").click(function() { var action = $("#form1").attr('action'); var form_data = { username: $("#username").val(), password: $("#password").val(), is_ajax: 1 }; $.ajax({ type: "POST", url: action, data: form_data, success: function(response) { if(response == 'success') $("#form1").slideUp('slow', function() { $("#message").html("<p class='success'>You have logged in successfully!</p>"); }); else $("#message").html("<p class='error'>Invalid username and/or password.</p>"); } }); return false; }); }); </script> </head> <body> <p> </p> <div id="content"> <h1>Login Form</h1> <form id="form1" name="form1" action="doLogin.php" method="post"> <p> <label for="username">Username: </label> <input type="text" name="username" id="username" /> </p> <p> <label for="password">Password: </label> <input type="password" name="password" id="password" /> </p> <p> <input type="submit" id="login" name="login" /> </p> </form> <div id="message"></div> </div> </body> </html> |
dogloin.php
代码如下 |
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<?php $is_ajax = $_REQUEST['is_ajax']; if(isset($is_ajax) && $is_ajax) { $username = $_REQUEST['username']; $password = $_REQUEST['password']; if($username == 'demo' && $password == 'demo') { echo "success"; } } ?> |
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