php sso单点登录实现代码
下面详细讲到了几点.1、点击登录跳转到SSO登录页面并带上当前应用的callback地址 2、登录成功后生成COOKIE并将COOKIE传给callback地址 3、callback地址接收SSO的COOKIE并设置在当前域下再跳回到应用1即完成登录 4、再在应用程序需要登录的地方嵌入一个iframe用来实时检测登录状态,代码如下:
<?php
//index.php 应用程序页面
header('Content-Type:text/html; charset=utf-8');
$sso_address = 'http://2spaoku.com/sso/login.php'; //你SSO所在的域名
$callback_address = 'http://'.$_SERVER['HTTP_HOST']
.str_replace('index.php','',$_SERVER['SCRIPT_NAME'])
.'callback.php'; //callback地址用于回调设置cookie
if(isset($_COOKIE['sign'])){
exit("欢迎您{$_COOKIE['sign']} <a href="login.php?logout">退出</a>");
}else{
echo '您还未登录 <a href="'.$sso_address.'?callback='.$callback_address.'">点此登录</a>';
}
?>
<iframe src="<?php echo $sso_address ?>?callback=<?php echo $callback_address ?>" frameborder="0" width="0" height="0"></iframe>
<?php
//login.php SSO登录页面
header('Content-Type:text/html; charset=utf-8');
if(isset($_GET['logout'])){
setcookie('sign','',-300);
unset($_GET['logout']);
header('location:index.php');
}
if(isset($_POST['username']) && isset($_POST['password'])){
setcookie('sign',$_POST['username'],0,'');
header("location:".$_POST['callback']."?sign={$_POST['username']}");
}
if(emptyempty($_COOKIE['sign'])){
?>
<form method="post">
<p>用户名：<input type="text" name="username" /></p>
<p>密 码：<input type="password" name="password" /></p>
<input type="hidden" name="callback" value="<?php echo $_GET['callback']; ?>" />
<input type="submit" value="登录" />
</form>
<?php
}else{
$query = http_build_query($_COOKIE);
echo "系统检测到您已登录 {$_COOKIE['sign']} <a href="{$_GET['callback']}?{$query}">授权</a> <a href="?logout">退出</a>";
}
?>
<?php
//callback.php 回调页面用来设置跨域COOKIE
header('Content-Type:text/html; charset=utf-8');
if(emptyempty($_GET)){
exit('您还未登录');
}else{
foreach($_GET as $key=>$val){
setcookie($key,$val,0,'');
}
header("location:index.php");
}
?>
<?php
//connect.php 用来检测登录状态的页面，内嵌在页面的iframe中
header('Content-Type:text/html; charset=utf-8');
if(isset($_COOKIE['sign'])){
$callback = urldecode($_GET['callback']);unset($_GET['callback']);
$query = http_build_query($_COOKIE);
$callback = $callback."?{$query}";
}else{
exit;
}
?>
<html><script type="text/javascript">top.location.href="<?php echo $callback; ?>";</script></html>永久链接：http://www.phprm.com/develop/fs5002.html
转载随意！带上文章地址吧。