<?php
$id = $_GET[id];
$sql = "select * from biao where pid=".$id;
$res = mysqli_query($conn,$sql);
$num = mysqli_num_rows($res);   //现有多少张图片
$sql1 = "select * from biao where id=".$id;
$res1 = mysqli_query($conn,$sql1);
$row1 = mysqli_fetch_assoc($res1);
$num1 = $row1[p_num];
$p_name = $row1[p_name];
?>

<form action="" method="post" enctype="multipart/form-data" name="form2">
<br>
<table width="750" border="1" align="center" cellpadding="0" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td height="25"  width="550" align="center" valign="middle" bgcolor="#FFFFFF"><font size="5">添  加  图  片</font></td>
<td height="25"  align="center" valign="middle" bgcolor="#FFFFFF"><input type="submit" name="fanhui" value="返回上一层"></td>
</tr>
</table>
<br>



<table width="750" border="1" align="center" cellpadding="0" cellspacing="1" bgcolor="#FFFFCC">
<tr>
    <td align="center" colspan="2">
  <p align="left"> 现已上传图片<?php echo $num?>张:</p>
  <p>图片名称1：<input type="text" name="name[]" size="25"><input type="hidden" name="tu1"/>  <input type="file" name="pictures[]" id="file1"  /></p><p></p>
  <p>图片名称2：<input type="text" name="name[]" size="25"><input type="hidden" name="tu2"/>  <input type="file" name="pictures[]" id="file2" /></p><p></p>
  <p>图片名称3：<input type="text" name="name[]" size="25">  <input type="file" name="pictures[]" id="file3" /></p><p></p>
  <p>图片名称4：<input type="text" name="name[]" size="25">  <input type="file" name="pictures[]" id="file1"  /></p><p></p>
  <input type="submit" name="upload" value="提交" />
  </td>
</tr>
</table>
  
</form>
</body>
</html>

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