php ajax XMLHttpRequest POST实例代码
php教程 ajax XMLHttpRequest POST实例代码
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "php教程">
<html xmlns="php教程">
<meta http-equiv="Content-Type" content="text/html;charset=UTF-8" />
<head>
<script type="text/php教程">
function showUser(str){
if(window.XMLHttpRequest){ // code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}else{ // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function(){
if(xmlhttp.readyState==4 && xmlhttp.status==200){
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("POST","ajax.php",true);
xmlhttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=utf-8;");
xmlhttp.send(q=+str);
}
</script>
</head>
<body>
<form method="post">
ajax的POST<input name="submit" type="submit" onclick="showUser(28);return false;" value="查询"/>
</form>
<form action="ajax.php" method="post">
真正的POST<input name="q" type="submit" value="28"/>
</form>
<br />
<div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
</html>
php 代码<?php
header(Content-Type:text/html;charset=utf-8;);
echo "POST数据: ".implode(,file(php://input));
echo "<br>POST[q] ".$_POST[q]."<br>";
print_r($_POST);
?>
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